In Reply to: about quiz 1 posted by 蘇慶峰 on March 21, 1997 at 11:10:03:
> 有關第二題的eigenvectors
> 利用Ae=eU --> (A-eI)u=0則發現u=0; (e is eigen value)
> 但我無找出 u=(cos(2@),sin(2@)) or (-sin(2@),cos(2@))
> 還是我算錯了
>
我想是你算錯了。
我在下堂課會再詳細解釋。
(BTW, the correct eigenvaector is [cos@, sin@]
and [-sin@, cos@].)