Liza, after the hole affair, was pretty upset with Henry. In an effort to get him to think, she had him fill a barrel with several different buckets. The barrel had to be filled exactly to the top by whole (or is that hole?) bucket quantities. Henry, being lazy, kept thinking about it until he could do it in the fewest buckets possible.
Sample Input A: Sample Input B: Sample Input C: 17 20 36 1 7 19 2 5 9 4 3 5 5 1 2 1 Sample Output A: Sample Output B: Sample Output C: 4 4 4
Example, this is a square:
1, 2; 2, 3; 3, 4; 4, 1;;
For the square above, the answer is ``2''.
abcdefgh 1........ 2........ 3........ 4...o*... 5...*o... 6........ 7........ 8........The board starts initially as above. Pieces are added, alternating between black and white, starting with black. A piece can be added on any square where there are interposing pieces of the opposite colour between that square and another of the same colour as the piece being played. No blanks can separate the pieces in question. All interposing pieces so bracketed are then changed to be the same as the colour played. Play can go on any horizontal, vertical or diagonal line. As an example, from the above starting position, black can play on squares c4, d3, f5, and e6. If we looked at white's possible moves, white could play on squares c5, d5, e3, and f4.
........ ........ ..ooo... .*o*o*.. .ooooo.. ...*.... ........ ........
(Black-White)=-6The value above (-6) is the number of black moves minus the number of white moves, as indicated.
Your task is to find all sets of anagrams that exist within a given dictionary of words. The input will be a list of words, one per line which will be incidentally sorted (being a dictionary and all...). The output shall consist of each of the sets of anagrams on a separate lines, the members separated by a single space (no trailing spaces). Please note that each set should be in alphabetical order, and all lines of sets should also be in alphabetical order. A word with no anagrams is considered a set of anagrams itself, and should be displayed with no modifications.
Input: Output: canter canter centra nectar recant trance centra destain instead sainted stained destain least slate stale steal instead post pots stop least start nectar post pots recant sainted slate stained stale start steal stop trance
The basic idea behind RLE is to replace, say, 20 consecutive occurrences of the character `.', with the number 20 and a single `.'. This variant allows runs to be longer than one character. For example, the sequence abcabcabcabcabc should be converted into 0503abc. The first two characters, 05, are a pair of digits specifying how many times the pattern is repeated; the next two characters, 03, are the length of the repeated pattern, and that many characters following (abc) is the pattern to be repeated, itself.
Each compression saves a certain number of characters. The digits are not to be counted in considering the length of the compressed sequence. In the example above, 12 characters were saved. Each string to be compressed will probably consist of more than one repeated pattern. For example, the string abcdabcdabcdefefefefgggggg should turn into 0304abcd0402ef0601g.
When compressing a string, always start by compressing the repeated sequence that saves the most characters first, and then compress what's left over on the left, and on the right. For example, the string aabbaabbbbaabb should be compressed as 0201a0206bbaabb and not as 0204aabb0106bbaabb or 0204aabb0202bb0202aa0202bb. If more than one such sequence exists, pick the longer one. If more than one have the same length, pick the one further to the right.
If a string has no repeating sequences, output it with no digits in front.
You will receive a number of lines of text on standard input. These lines will not contain digits. You are to compress each one as described above, and write your answer to standard output. Use one line of output for each line of input.
abcdabcdabcdefefefefgggggg aabbaabbbbaabb bananananas fors fors aaaaa a a aaaaaa aaaaa a a aaaa
0304abcd0402ef0601g 0201a0206bbaabb ba0402nas0205 fors 0401a0302a 0601a 0501a0302 a0301a